freqz produces incorrect output

Frederick_Umminger at playstation.sony.com Frederick_Umminger at playstation.sony.com
Wed Dec 24 15:21:08 CST 2008


I believe the following code fixes the problem. I apologize for it not 
being a diff.

-Frederick


## Copyright (C) 1994, 1995, 1996, 1997, 1999, 2000, 2002, 2005, 2006,
##               2007 John W. Eaton
##
## This file is part of Octave.
##
## Octave is free software; you can redistribute it and/or modify it
## under the terms of the GNU General Public License as published by
## the Free Software Foundation; either version 3 of the License, or (at
## your option) any later version.
##
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## WITHOUT ANY WARRANTY; without even the implied warranty of
## MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE.  See the GNU
## General Public License for more details.
##
## You should have received a copy of the GNU General Public License
## along with Octave; see the file COPYING.  If not, see
## <http://www.gnu.org/licenses/>.

## -*- texinfo -*-
## @deftypefn {Function File} {[@var{h}, @var{w}] =} freqz (@var{b}, 
@var{a}, @var{n}, "whole")
## Return the complex frequency response @var{h} of the rational IIR 
filter
## whose numerator and denominator coefficients are @var{b} and @var{a},
## respectively.  The response is evaluated at @var{n} angular frequencies
## between 0 and
## @ifinfo
##  2*pi.
## @end ifinfo
## @iftex
## @tex
##  $2\pi$.
## @end tex
## @end iftex
##
## @noindent
## The output value @var{w} is a vector of the frequencies.
##
## If the fourth argument is omitted, the response is evaluated at
## frequencies between 0 and
## @ifinfo
##  pi.
## @end ifinfo
## @iftex
## @tex
##  $\pi$.
## @end tex
## @end iftex
##
## If @var{n} is omitted, a value of 512 is assumed.
##
## If @var{a} is omitted, the denominator is assumed to be 1 (this
## corresponds to a simple FIR filter).
##
## For fastest computation, @var{n} should factor into a small number of
## small primes.
##
## @deftypefnx {Function File} {@var{h} =} freqz (@var{b}, @var{a}, 
@var{w})
## Evaluate the response at the specific frequencies in the vector 
@var{w}.
## The values for @var{w} are measured in radians.
##
## @deftypefnx {Function File} {[@dots{}] =} freqz (@dots{}, @var{Fs})
## Return frequencies in Hz instead of radians assuming a sampling rate
## @var{Fs}.  If you are evaluating the response at specific frequencies 
## @var{w}, those frequencies should be requested in Hz rather than 
radians.
##
## @deftypefnx {Function File} {} freqz (@dots{})
## Plot the pass band, stop band and phase response of @var{h} rather
## than returning them.
## @end deftypefn

## Author: jwe ???

function [h_r, f_r] = freqz (b, a, n, region, Fs)
  if (nargin < 1 || nargin > 5)
    print_usage ();
  elseif (nargin == 1)
    ## Response of an FIR filter.
    a = n = region = Fs = [];
  elseif (nargin == 2)
    ## Response of an IIR filter
    n = region = Fs = [];
  elseif (nargin == 3)
    region = Fs = [];
  elseif (nargin == 4)
    Fs = [];
    if (! ischar (region) && ! isempty (region))
      Fs = region; 
      region = [];
    endif
  endif

  if (isempty (b))
    b = 1;
  endif
  if (isempty (a)) 
    a = 1; 
  endif
  if (isempty (n))
    n = 512; 
  endif
  if (isempty (region))
    if (isreal (b) && isreal (a))
      region = "half";
    else
      region = "whole";
    endif
  endif
  if (isempty (Fs)) 
    if (nargout == 0) 
      Fs = 2; 
    else 
      Fs = 2*pi; 
    endif
  endif

  a = a(:);
  b = b(:);

  if (! isscalar (n)) ## Explicit frequency vector given
    w = f = n;
    if (nargin == 4)  ## Sampling rate Fs was specified
      w = 2*pi*f/Fs;
    endif
    k = max (length (b), length (a));
    hb = polyval (postpad (b, k), exp (j*w));
    ha = polyval (postpad (a, k), exp (j*w));
  else
      ## polyval(fliplr(P),exp(jw)) is O(p n) and fft(x) is O(n log(n)),
      ## where p is the order of the polynomial P.  For small p it
      ## would be faster to use polyval but in practice the overhead for
      ## polyval is much higher and the little bit of time saved isn't
      ## worth the extra code.
      if (strcmp (region, "whole"))
        N= n;
      else
        N = 2*n;
      endif
 
      f = Fs * (0:n-1)' / N;
 
      sz = max(size(b,1), size(a,1));
      pad_sz = N*ceil(sz/N);
      b = postpad(b,pad_sz);
      a = postpad(a,pad_sz);
 
      hb = zeros(n,1);
      ha = zeros(n,1);
 
      for i = 1:N:pad_sz
        hb = hb + fft (postpad (b(i:i+N-1), N))(1:n);
        ha = ha + fft (postpad (a(i:i+N-1), N))(1:n);
      endfor
 
  endif

  h = hb ./ ha;
  if (nargout != 0), # return values and don't plot
    h_r = h;
    f_r = f;
  else             # plot and don't return values
    freqz_plot (f, h);
  endif

endfunction

%!test # correct values and fft-polyval consistency
%! # butterworth filter, order 2, cutoff pi/2 radians
%! b = [0.292893218813452  0.585786437626905  0.292893218813452];
%! a = [1  0  0.171572875253810];
%! [h,w] = freqz(b,a,32);
%! assert(h(1),1,10*eps);
%! assert(abs(h(17)).^2,0.5,10*eps);
%! assert(h,freqz(b,a,w),10*eps); # fft should be consistent with polyval

%!test # whole-half consistency
%! b = [1 1 1]/3; # 3-sample average
%! [h,w] = freqz(b,1,32,'whole');
%! assert(h(2:16),conj(h(32:-1:18)),20*eps);
%! [h2,w2] = freqz(b,1,16,'half');
%! assert(h(1:16),h2,20*eps);
%! assert(w(1:16),w2,20*eps);

%!test # Sampling frequency properly interpreted
%! b = [1 1 1]/3; a = [1 0.2];
%! [h,f] = freqz(b,a,16,320);
%! assert(f,[0:15]'*10,10*eps);
%! [h2,f2] = freqz(b,a,[0:15]*10,320);
%! assert(f2,[0:15]*10,10*eps);
%! assert(h,h2.',20*eps);
%! [h3,f3] = freqz(b,a,32,'whole',320);
%! assert(f3,[0:31]'*10,10*eps);




Frederick Umminger/R&D/SCEA 
12/24/2008 12:53 PM

To
bug at octave.org
cc
Frederick Umminger/R&D/SCEA at Playstation
Subject
freqz produces incorrect output





Bug report for Octave 3.0.3 configured for i686-pc-msdosmsvc

Description:
-----------

  The command [h,w] = freqz(b) produces an incorrect answer if the vector 
b has length greater than 512. 
  Similarly for [h,w] = freqz(b,a) , [h,w] = freqz(b,a,n) if the length of 
b or a is greater than 512, n respectively.


Repeat-By:
---------

% Compute the spectrum of an audio file
[audio, fs]  = auload("InputSample.wav");
[h_audio, w_audio] = freqz(audio );

Fix:
---

  This is because the branch of the code that uses the fft as a 
replacement for polyval has an implicit assumption about relative sizes. 
If this assumption is violated, then the call to postpad truncates b and 
a.
  In order to be correct, this code must be rewritten to sum over multiple 
ffts when either b or a is larger than n.




Configuration (please do not edit this section):
-----------------------------------------------

uname output:     Windows
configure opts: 
Fortran compiler: fc-msvc
FFLAGS:           -O2
F2C:              @F2C@
F2CFLAGS:         @F2CFLAGS@
FLIBS:            -lhdf5 -lzlib -lf2c -lkernel32
CPPFLAGS:         -I.  -Ic:/Software/VCLibs/include
INCFLAGS:         -I. -I. -I./liboctave -I./src -I./libcruft/misc
C compiler:       cc-msvc, version
CFLAGS:           -O2 -MD
CPICFLAG: 
C++ compiler:     cc-msvc, version
CXXFLAGS:         -O2 -EHs -MD
CXXPICFLAG: 
LD_CXX:           cc-msvc
LDFLAGS: 
LIBFLAGS:         -L.
RLD_FLAG: 
BLAS_LIBS:        -llapack -lblas
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User-preferences (please do not edit this section):

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