"y \= scalar" fails

[Rolf Fabian]

Jaroslav Hajek-2 wrote:
> 
> this seems 100% correct. 
> y \= c means y = y \ c = inv(y) * c, 
> 

Thanks for explaining me, what a backslash
division is supposed to do.



> but size(y,2) != size(c,1).
> 

Unfortunately you forgot to line out the
problem which Octave has to multiply a
square matrix by a scalar value. i.e.
evaluating "inv(y) * c" .
Is "inv(y) * c" not anymore identical
to "inv(y) .* c" or did I miss something?



> Matlab gripes as well here.
> 
> RNDr. Jaroslav Hajek
> computing expert
> Aeronautical Research and Test Institute (VZLU)
> Prague, Czech Republic
> url: www.highegg.matfyz.cz
> 

There seem to be many features of ML which
are weird, strange or obscure. They do not
necessarily have to be merged into Octave
without critically reflecting them.


-----
Rolf Fabian
<r dot fabian at jacobs-university dot de>

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