1 & nan

[John W. Eaton]

On 11-Jul-2008, G.. wrote:

| Is there a particular reason that
| 
| 1 & nan = 1
| 
| while 1 +/* nan = nan?

I checked in the following change to the default Mercurial branch to
make Octave's behavior more compatible with Matlab in this case.

jwe

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