attach y2 to y1

[Martin Weiser]

On Tue, 9 Jun 2009, feldmaus wrote:

> Hi All,
>
> i want to attach the result of the discharge function u2 to the result of a
> charge function u1 , so how to do that?
>
> T=1e-6
> t1=0:0.1e-6:1e-6;
> t2=1e-6:0.1e-6:3e-6;
> U0=1
> u1=U0*(1-exp(-t1/T))
> u2=U0*exp(-t2*T)
>
> i do not want to plot to function on one figure.
> After this i want to make the fft of u.
>
> Any hints
>
> regards Markus
>
> _______________________________________________
> Help-octave mailing list
> Help-octave at octave.org
> https://www-old.cae.wisc.edu/mailman/listinfo/help-octave
>
>
Hello,
if hints are enough, then: please read the manual - you are not doing 
anything special.
To be more specific (maybe you are lost, and really need some help...),
(I am not at my Octave machine yet, so check the syntax, please)I would guess
that something like this would work (replace ... with values that are
appropriate):
Start the octave, wait for the prompt. Type in:
T=...
U=...
t1=[...:...:...]; #[lower bound, step, upper bound]
t2=[...:...:...]; #detto
u1=U0.*(1-exp(-t1./T));
u2=U0.*(1-exp(-t2.*T));
plot([u1,u2])

I have no experience with fft and I do not have the will to read the 
manual for you, but you can find it here:
http://www.gnu.org/software/octave/doc/interpreter/
Good luck.
Martin W.