plot templates and options lists for set, plot etc.
Ben Abbott
bpabbott at mac.com
Sun Jul 5 10:37:47 CDT 2009
On Jul 5, 2009, at 7:23 AM, Thorsten Meyer wrote:
> Hi,
>>
>> I'm running Matlab 2009a
>>
>> x = 0:0.01:5;
>> h(1) = line (x, sin(x));
>> h(2) = line (x, cos(x));
>> s(1,1).Color = 'red';
>> s(1,2).Color = 'green';
>> set (h, s);
>> color = get (h, 'color');
>> color{:}
>> ans =
>> 0 1 0
>> ans =
>> 0 1 0
>>
>> I'd expected the lines to have different colors.
> Could you also try
> h(1) = line (x, sin(x));
> h(2) = line (x, cos(x));
> s(1,1).Color = 'red';
> s(2,1).Color = 'green';
> set (h, s);
> color = get (h, 'color');
> color{:}
> ?
My usual computer is in for repair. My second machine is PPC based and
is only able to run Matlab R2007b. I had to add the 3rd line below to
run your script, but the results are not correct.
>> h(1) = line (x, sin(x));
>> h(2) = line (x, cos(x));
>> s = struct ();
>> s(1,1).Color = 'red';
>> s(2,1).Color = 'green';
>> set (h, s);
>> color = get (h, 'color');
>> color{:}
>> ans =
0 1 0
>> ans =
0 1 0
>>
>> I also tried the following ...
>>
>> property_names = {'color', 'color'};
>> property_values = {[1,0,0], [0,1,0]};
>> set (h, property_names, property_values)
>> color = get (h, 'color');
>> color{:}
>> ans =
>> 0 1 0
>> ans =
>> 0 1 0
>>
>> It appears that the property names and values are each applied to all
>> handles. The green sticks because it was set last.
> Could you try again with
> property_names = {'color'};
> property_values = {[1,0,0]; [0,1,0]};
> set (h, property_names, property_values)
> color = get (h, 'color');
> color{:}
> ?
>> property_names = {'color'};
>> property_values = {[1,0,0]; [0,1,0]};
>> set (h, property_names, property_values)
??? Error using ==> set
Value cell array handle dimension must match handle vector length.
But this does work
>> x = 0:0.01:5;
>> h(1,1) = line (x, sin(x));
>> h(2,1) = line (x, cos(x));
>> pn = {'Color'};
>> pv = {'red'; 'green'};
>> set (h, pn, pv);
>> color = get (h, 'color');
>> color{:}
>> ans =
1 0 0
>> ans =
0 1 0
Ben
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